Linear search in c: The following code implements linear (search algorithm) search is used to determine whether a given number is in a table in place and yet when it then place it occurs. It is also called sequential search. It is very simple and works as follows: Followed by each element with the element looking to compare until you find the desired item or the list ends.
/* Linear search c program */
Linear search for multiple occurrences
Linear search using function in C
Linear search function using pointers in C
/* Linear search c program */
#include <stdio.h>
int main()
{
int array[100], search, c, n;
printf("Enter the number of elements in array\n");
scanf("%d",&n);
printf("Enter %d integer(s)\n", n);
for (c = 0; c < n; c++)
scanf("%d", &array[c]);
printf("Enter the number to search\n");
scanf("%d", &search);
for (c = 0; c < n; c++)
{
if (array[c] == search) /* if required element found */
{
printf("%d is present at location %d.\n", search, c+1);
break;
}
}
if (c == n)
printf("%d is not present in array.\n", search);
return 0;
}
int main()
{
int array[100], search, c, n;
printf("Enter the number of elements in array\n");
scanf("%d",&n);
printf("Enter %d integer(s)\n", n);
for (c = 0; c < n; c++)
scanf("%d", &array[c]);
printf("Enter the number to search\n");
scanf("%d", &search);
for (c = 0; c < n; c++)
{
if (array[c] == search) /* if required element found */
{
printf("%d is present at location %d.\n", search, c+1);
break;
}
}
if (c == n)
printf("%d is not present in array.\n", search);
return 0;
}
Output:
Enter the number of elements in array
6
Enter 6 numbers
5
6
9
2
4
7
Enter the number to search
2
2 is present at location 3.
Read More:Enter the number of elements in array
6
Enter 6 numbers
5
6
9
2
4
7
Enter the number to search
2
2 is present at location 3.
Linear search for multiple occurrences
Linear search using function in C
Linear search function using pointers in C
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